ACT Past Papers with Answers

Paper 41

ACT December 2014

Form 72G · Science Test · 40 questions

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Paper 41 · ACT December 2014 · Form 72G · Science Test

According to Figures 2 and 3, the flies with the geno type associated with the least amount of recovery sleep per day had a maximum life span of:

A60days.B70days.C80days.D100days.

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Paper 41 · ACT December 2014 · Form 72G · Science Test

Why, for a given H, is the object's acceleration greatest when the top of a spring is a distance y meters below its initial position? GO ON TO THE NEXT PAGE. 410i\.CT 微信号 loviact 独角兽在这里 4 Passage Ill The tropopause is the transition between 2 layers of Earth's atmosphere: the troposphere ( the layer that begins at Earth's surface) and the stratosphere (the layer just above the troposphere). Figure I shows how air tempera ture changes with altitude at3 latitudes (0° , 45 ° N, and 90° N), as well as the average tropopause altitude for each of those latitudes. Figure2 shows, for the tropical latitudes, the monthly averages for tropopause altitude, tropopause airpressure, and tropopause air temperature determined for a particular30-year period. 27 24 21 18 ^ 815 名已 12 ．＿ .... G 一 3 9 6 3 。 : I ; ；，；， .../....令．．．金..矗．．．．；｀·合..合.)..:....;.......一；．．．．． ,; ,I : : : : ': : I : ! :____..;-average tropopause , I :I : ＇， r i altitudefor0° .. ...;!..···_:;.;;-r·..·t-t.........!.........,...................., ，． :：＇average tropopause ` ：、 ; altitude for45° N .．．．．．．，.i.．、一、、＿＿：．．譬．．．．；．．．．．；．．．．．．．．．4.．．．．．．．．；金·•••••••;．．．．．．．．．; ｀、、. average tropopause :、：altitudefor90° N ．．．晕·••·r • • • J .、, ．．．；．．．．．．．．．？•••••••·,．．．．．.．．．．． : ： , 、` : ； ; ＇， .. : , ·. '、、 : ；， : : : ．. ：、、; ； : .．．．.．，·:•••••••••-_，．．．．．.．．．．．．．．．．．．．．．．．.．．．．．．．.．．．．．．．..．．．．．．俨．，．．．．．．．.... : t. ：？、； : 、： :.. : ... : : ： ; ·4 . 、、； :'• ：、 ;.．．．．．．．+,•••••••:••••••·',.,．．.•嘈·••~..．．．.,．．．.．、．．;．．,．．，··妇................... ; ·•.; ｀ .. ：、 : ·· : .、: ; ••: ＇、．气． .、 ......,..........j.....,........;.........,.......·,,.、·••·.．．．．匕．．．．．．：． } ：：：； , •• : ： ..、： : : : ; ··j . 、... 凸：：、 · ; . ： •··. 、、 -80-70 -60 -50-40-30 -20 -10 0 10 20 airtemperature(0 Figure 1 Figure 1 adapted from Frederick Lutgens, Edward Tarbuck, and Dennis Tasa, The Atmosphere, 11thed. ©2001by Prentice Hall. ACT-72G 42 � 17.0 甘口尸。二 16.4 哿呈 5 `16.2] .．．．．．．．．．．．．． � 16.0 、心穸令令、心f '�'b-4,<.;丸令飞豆，求o。冷飞e e 匠I �．一｀叶器 g巳 94 « 、心穸令令沁、汽心｀飞心斗，求oc,'- ·�。飞0 e 长－76 宇:, -78] 仁匕＂ o 匕 g导－80,--··· 5出＿84 计－82 巨总、心穸心令、立＄汽｀｀飞沁、豆溪o。冷飞e o Figure2 Figure 2adapted from Dian Seidel et al., "Climatological Character istics of the Tropical Tropopause as Revealed by Radiosondes." ©2001by American Geophysical Union. GO ON TO THE NEXT PAGE. 4101\.CT 微信号loviact 独角兽在这里 4 11. According to Figure 1, at 45° N latitude, the air tern perature at Earth's surface is closest to which of the following? C C C C

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Paper 41 · ACT December 2014 · Form 72G · Science Test

According to Figure 1, at 0° latitude, how does the air temperature in the troposphere change with increasing altitude from Earth's surface.to the tropopause, and how does the air temperature in the stratosphere change with increasing altitude from the tropopause to 27 km ? troposphere stratosphere GO ON TO THE NEXT PAGE. 410}\.CT 微信号loviact 独角兽在这里 4 Passage IV Companies W-Z were suspected of diluting pure (100%) honey before packaging it for sale. Students inves tigated each company's product by using the process of osmosis. During osmosis, H20 flows across a semiperme able membrane (such as dialysis tubing) from a solution having a lower solute concentration into one with a higher solute concentration. Smaller molecules (such as H20) can pass through tiny pores in the dialysis tubing, but larger molecules (such as sugars) cannot. Experiment 1 Two mL of 100% honey was mixed with 8 mL of H20 to form a 20% honey solution. A 40%, a 60%, and an 80% honey solution were also made. A sample of 1 of the 4 solutions, 100% honey, or pure H20 was added to each of 6 bags made of dialysis tubing. Air was pressed out of the bags, the bags were sealed, and the initialmass of each bag plus its contents was measured. Each bag was fully sub merged in a separate beaker of pure H20 at 25° C for 2 hr. The bags were then removed and dried off, and the final mass of each bag plus its contents was measured (see Table 1). Table 1 Initial Final Percent mass mass change Sample (g) (g) m mass 20% honey 11.2 13.4 20 40% honey 11.6 15.3 32 60% honey 12.2 17.7 45 80% honey 13.6 24.1 77 100% honey 14.5 28.3 95 Pure H20 10.2 10.2 。 ACT-72G 44 Experiment 2 A sample of each company's product was added to a separate bag and tested as in Experiment 1 (see Table2). Table 2 Sample Initial Final Percent from mass mass change Company (g) (g) m mass w 14.1 27.6 96 X 13.8 26.9 95 Y 13.1 24.3 85 z 13.9 25.0 80 Tables adapted from Don't Blame the Bees: Teacher's Guide. ©2000 by Carolina Biological Supply Company. Experiment 3 A sample of Company Z's product was added to 5 bags. The samples were tested as in Experiment 1, except that the bag$ were submerged in separate beakers contain ing, respectively, 20%, 40%, 60%, 80%, or 100% honey. The mass of the bag plus its contents increased for 4 of the bags, but decreased for 1 of the bags. GO ON TO THE NEXT PAGE. 410n.CT 微信号_ Iovi ac� 独角兽在这里 4 16. Suppose that in Experiment I the students had also tested a 70% honey solution. Based on the results of Experiment 1, the percent change in mass would most likely have been between:

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Paper 41 · ACT December 2014 · Form 72G · Science Test

In Experiment 3, the mass of I of the bags plusits con tents decreased. This bag had most likely been sub merged in the beakercontaining: GO ON TO THE NEXT PAGE. 410}\.CT 微信号loviact 独角兽在这里 4 Passage V When an electrical current flows through a metal strip in a magnetic field, a magnetic force is exerted on some electrons in the strip. These electrons are pushed to an edge of the strip, making that edge negatively charged (see Figure I). current current Figure 1 The opposite edge of the strip, which develops a shortage of electrons, becomes positively charged, and so a voltage, VH, develops between these 2 edges of the strip. A physics class conducted 3 studies of this phenome non, called the Hall effect. In each trial of the studies, an aluminum strip having a thickness d was clamped to a ring stand. The 2 ends of the strip were connected to an electrical circuit containing a DC power supply, and the 2 edges of the strip were con nected to a voltmeter (see Figure 2). from DC power supply d工 ring stand Figure 2 ACT-72G 46 The strip was also positioned horizontally between the poles of an electromagnet (see Figure 3). to DC power supply 气 side view Figure 3 voltmeter from DC power supply The students adjusted the power supply output as needed so that the desired current, /, flowed through the strip. Finally, the students adjusted the electromagnet as needed to pro duce the desired magnetic field strength, B, and recorded the re�ulting VH. Study I With d equal to 15 mm and B equal to 0.6 tesla-(T), the students found VH, in nanovolts (nV; I nV = 10-9 V), for various /, in amperes (A) (see Table 1). Table1 Trial I (A) VH (nV) l IO 13 2 15 19 3 20 25 4 25 32 Study 2 With d equal to 15 mm and / equal to 25 A, the stu dents found V8 for various B (see Table 2). Table 2 Trial B (T) VH (nV) 5 0.2 11 6 0.4 21 7 0.8 42 8 1.0 53 GO ON TO THE NEXT PAGE. 4101t\.CT 微信号loviact 独角兽在这里 4 Study 3 With B equal to 0.6 T and/ equal to 25 A, the students found VH for various d(see Table 3). Table 3 Trial d(mm) 咋(nV) 9 3 160 10 6 79 11 9 53 12 12 40

A40% honey.B60% honey.C80% honey.DI00% honey.

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Paper 41 · ACT December 2014 · Form 72G · Science Test

Based on the results of the studies,·which of山e fol lowing equations correctly relates VH to/, B, andd? (Note: k is a constant.) Bd Id I d ACT-72G 47 GO ON TO THE NEXT PAGE. 410:A.CT 微信号loviact 独角兽在这里 4 Passage VI A science teacher lights a new wax candle (which, if left undisturbed, would burn for several hours) in her class room. She then shows her students a glass jar and asks them to predict what will happen if she places the jar over the lit candle, completely sealing off the candle from the surrounding atmosphere (see figure). Four students give their viewpoints about why the candle burns and about what will happen to the burning candle once it is under thejar. Student 1 The candle's flame results from a combustion reac tion. When the candle is lit, the flame that lights the candle heats the candle, which causes the candle to give off fumes of wax. The wax fumes act as a fuel that reacts with the 02 present in the air. The reaction gives off energy, which heats the surrounding air, producing a flame. If the jar is placed over thelit candle, the candle will soonstop burning because the 02 in the air under the jar will be quickly used up. ACT-72G 48 Student 2 Student 1 is correct except that the fuel reacts with the N2, not with the 02, in the air. Student 3 None of the components of air are involved in the burning of the candle. When the candle is lit, the energy from the flame causes the fuel (candle wax fumes) to spon taneously decompose. The heat from the decomposition reaction causes the reaction to continue. Thus, if thejar is placed over the lit candle, the candle will continue to burn until all of the fuel is used up. Student4 When the candle is lit, the energy from the flame causes the fuel (candle wax fumes) to spontaneously decompose into a massless substance called heat. None of the components of air chemically react with the fuel, but the 02 present in air is necessary for the sustained decom position reaction. The 02 is needed because as the heat is produced, the heat must be absorbed for the reaction to continue, and 02 is the only component of air that absorbs heat. When 02 absorbs heat, the 02 is not chemically altered. If the jar is placed over the lit candle, the candle will soon stop burning because the 02 in the air under the jar will quickly become saturated with heat.

AVH =k__J_BVH =k且CVH :::::k坦DVH =k旦

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Paper 41 · ACT December 2014 · Form 72G · Science Test

At each of the 3 sites, the grass plot and the shrub plot were adjacent. This arrangement ensured that which of the following variables could be assumed to be nearly identical for both plots during the studies? END OFTEST 4 STOP! DO NOT RETURN TO ANY OTHER TEST. ACT-72G 51 2014年12⽉月ACT试题（72G）答案 English Mathematics Readling Science 1 D L 1 D 31 C 1 C 1 A 2 J O 2 F 32 G 2 F 2 F 3 C V 3 B 33 E 3 B 3 C 4 G I 4 H 34 K 4 H 4 F 5 C 5 B 35 D 5 D 5 C 6 G 41 B 6 H 36 G 6 H 6 H 7 D 42 F 7 B 37 C 7 D 7 D 8 F 43 A 8 K 38 J 8 F 8 J 9 A 44 H 9 C 39 C 9 A 9 D 10 J 45 C 10 K 40 G 10 G 10 G 11 C 46 J 11 C 41 E 11 D 11 C 12 H 47 D 12 G 42 J 12 J 12 G 13 B 48 F 13 D 43 D 13 C 13 C 14 F 49 D 14 F 44 G 14 F 14 G 15 A 50 J 15 E 45 C 15 C 15 D 16 G 51 C 16 H 46 K 16 H 16 H 17 A 52 J 17 A 47 E 17 D 17 A 18 G 53 A 18 H 48 G 18 H 18 H 19 C 54 J 19 B 49 B 19 D 19 B 20 G 55 D 20 F 50 K 20 G 20 H 21 B 56 F 21 D 51 D 21 D 21 D 22 J 57 A 22 F 52 K 22 H 22 F 23 C 58 G 23 C 53 E 23 C 23 B 24 J 59 C 24 K 54 G 24 G 24 G 25 D 60 J 25 A 55 A 25 D 25 A 26 H 61 C 26 J 56 K 26 J 26 H 27 A 62 H 27 A 57 D 27 B 27 D 28 G 63 D 28 H 58 F 28 H 28 J 29 D 64 F 29 A 59 A 29 A 29 D 30 F 65 C 30 H 60 J 30 G 30 F 31 B 66 J 31 B 31 B 32 G 67 A 32 G 32 J 33 B 68 G 33 A 33 A 34 G 69 B 34 J 34 F 35 D 70 H 35 D 35 B 36 F 71 A 36 H 36 H 37 D 72 G 37 A 37 A 38 H 73 C 38 G 38 F 39 A 74 J 39 A 39 C 40 G 75 C 40 F 40 J 微信号: loviact QQ交流群：411-279-476 在线真题：loviact.com 2016年第六版 Lovi lOVACT 微信号loviact 独角兽在这里 Explanation of Procedures Used to Obtain Scale Scores from Raw Scores On each of the four tests on which you marked any responses, the total number of correct responses yields a raw score. Use the table below to convert your raw scores to scale scores. For each test, locate and circle your raw score or the range of raw scores that includes it in the table below. Then, read across to either outside column of the table and circle the scale score that corresponds to that raw score. As you determineyour scale scores, enter them in the blanks provided on the right. The highest possible scale score for each test is

AC content of the soilBN content of the soilCDominant plant speciesDClimate

Form 72G · Science Test · 40 questions

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