ACT Past Papers with Answers

Paper 86

ACT January 2001

Form 56B · Science Test · 40 questions

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Paper 86 · ACT January 2001 · Form 56B · Science Test

According to Hypothesis 2, the origin of most of the matter composing the Moon was most likely which of the following objects?

AA star far from the SunBEarthC·MarsDThe Sun

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Paper 86 · ACT January 2001 · Form 56B · Science Test

Which of the following assumptions regarding the Moon's origin is implicit in Hypothesis 1 ? that of Earth's core. ACT-56B-SAMPLE 37 GO ON TO THE NEXT PAGE. 4 eoVIACT 拉惶学豌微信号 loviact 独角兽在这里 4 Passage II Large cities have their own climate that differs from the climate in adjacent suburban and rural areas. A scien tist performed the following studies to learn more about an urban climate. Study I Air temperatures, in degrees Celsius (° recorded hourly over a 24-hour period at 3 sites: the center of a large city (the urban site), an adjacent suburban site, and a nearby rural site. This was done on 30 consecutive days during summer and 30 consecutive days during winter. Each hourly temperature was averaged over the given season. The results are in Figure 1. Key urban suburban rural Study 2 A site in the city was selected where a large concrete parking lot was located next to a large grassy area. After the parking lot and grassy area had been exposed to full sunlight for 8 hours, air temperaturereadings were taken at the surface every 20 meters (m) across the concrete and grass, starting at the center of the parking lot. The results are in Figure 2. , 0 4 2 0 8 6 4 2 0 l l 1 concrete grass 20 40 60 80 100 120 140 160 180 200 220 240 260 280 300 distance (m) a m re J a d rn a l mi ( 3 ° ) am 1 8 J 3 Q UI 3 1 目 ( U ° ) +30 +25 +20 +15 +10 +5 。。 -5 -10 -15 -20 l 、 12 midnight 3 .／_．一、、＼ // / ～＼、 \ 6 summer 9 12 noon ' -＿ ;. . -- 一· 、- ＿＿＿，多、、｀ --- 、`｀ -=- 夕？z ．一·一· Figure 2 winter 3 6 9 12 midnight Study 3 Weather instruments were used to measure the wind velocity on 30 days at various altitudes above the 3 sites used in Study l. The wind velocities, in kilometers per hour (km/hr), were used to generate the wind profiles shown in Figure 3. ( E ) 名 n m I e 450 300 150 。 windvelocity (km/hr) 0 6 12 18 24 30 wind velocity ·····•···················-··••f-••········· (km/hr) --·一一一一一...一一一一．．．．．一一．．．．．．．．．．．．．． 0 6 12 18 24 30 windvelocity ＿＿＿＿＿，一一·---·····-·····-··�·····--··』··--····---···········-·'··-·-······ (km/hr) ....一 0 6 12 18 24 30 urban site suburban site rural site 12 3 midnight 6 9 12 noon 3 6 9 12 血dnight Figure 3 Figure 1 白gures adapted from W. M. Marsh, Earthscape: A Physical Geography. ©1987 by John Wiley and Sons, Inc ACT-56B•SAMPLE 38 GO ON TO THE NEXT PAGE. 4 eoVIACT 书立忖E 芩：阳E 微信号loviact 独角兽在这里 4 Study 4 The scientist kept track of the amount of cloud cover and precipitation daily for 3 years iii the city and the rural area. It was found that the city had 10% more cloudy or hazy days and 10% more precipitation than the rural area. Air quality measurements revealed that the city air con tained 10 times more dust particles than rural air.

AThe Moon is older than Earth.BThe Moon isyounger than Earth.CThe Moon still has active volcanoes.DThe Moon's surface composition is identical toE, were6o ) 3 3 P } n s 1 e 3 J 己 g J 3 O UI 3 1 J - e

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Paper 86 · ACT January 2001 · Form 56B · Science Test

According to Study 3, wind velocity in urban areas mcreases: suburban areas. suburban areas. rural areas. rural areas. ACT-56B-SAMPLE 39 GO ON TO THE NEXT PAGE. 4 eOVIACT 扛2 怍E #: 历; 微信号 loviact 独角兽在这里 4 Passage Ill A chemist performed 3 experiments to determine the boiling points and freezing points of purified water (H20) and solutions of various types of solids dissolved in H20. Experiment 1 Fifty milliliters (mL) of H20 was heated in a beaker. The temperature of the H20 was recorded every 2 minutes (min) until it remained constant, indicating the boiling point. The procedure was repeated with a solution of 5 grams (g) of sodium chloride (NaCl) in 50 mL of H20 and with 10 g of NaCl in 50 mL of H20. The results are shown in Figure1. 108 102 96 90 84 78 72 ( U ° ) glll ll J1ldUI;i l . •.....•. (i).. .r.i. .• (i)... 于一. - 曹，一酝咖一． ...．／江矗 {•••• I,I.. � I f... J OO I.. jI'/ ／心 /,; l ｀卜，［．．．压牍 O 『一一忙－＋ 5 gNaCl ． ......-@...., +10 gNaCl 1 。 66 60 54 48 42 36 30 24 18 12 6 0 4,、6 8 10 12 14 16 18 20 22 24 26 28 30 time (min) Figure1 Figure adapted from M. Lesser, C. Constant, and J. Weisler, Contemporary Science - Book 3. ©1978 by Amsco School Publications, Inc. Experiment 2 A beaker containing 50 mL of H20 was placed in a dry ice bath (an insulated bowl of solid CO2, which pro duces temperatures below—70° solidify, the temperature was recorded. The procedure was repeated with various amounts of NaCl added to 50 mL of 比0. The percentages of NaCl by mass, the masses of NaCl, and the freezing points are shown in Table 1. Table 1 Mass of NaCl Freez ( i O n C g ) point Solution %NaCl (g) 1 。 0.0 0.00 2 3 1.5 -1.85 3 6 3.0 -3.63 4 9 5.0 -5.77 5 13 7.5 -9.03 6 17 10.0 -12.30 Experiment 3 The freezing points of various solutions of potassium chloride (KCl) and calcium chloride (CaC 12) were mea sured using the same method as in Experiment 2. The results are shown in Tables2 and3. Table2 Mass ofKCI Freez ( iOn C g ) point Solution % KCl (g) 7 3 1.5 -1.48 8 6 3.0 -2.80 9 9 5.0 -4.30 10 13 7.5 -6.45 11 17 10.0 N.M.* * Not measured Table3 Mass of CaC 12 Freez ( iOn C g ) point Solution %CaCl2 (g) 12 3 1.5 -1.47 13 6 3.0 -2.93 14 9 5.0 -5.04 15 13 7.5 -8.72 16 17 10.0 -13.65

Amore rapidly with altitude than wind velocity inBat the same rate with altitude as wind velocity inCat the same rate with altitude as wind velocity inDmore slowly with altitude than wind velocity inE. When the H20 began to

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Paper 86 · ACT January 2001 · Form 56B · Science Test

Which of the following procedures would most likely raise the freezing_ point of all of the sol斗tions measured in Experiment3 ? solution ACT-56B-SAMPLE 41 GO ON TO THE NEXT PAGE. 4 eoVIACT ，立惶学院微信号loviact 独角兽在这里 4 Passage IV A scientist tested the ability of 4 drugs to kill cancer cells. Experiment 1 Permeability coefficients measure a drug's ability to enter a cell. The larger the permeability coefficient, the faster the drug enters a cell. The molecular mass, in atomic mass units (amu), and permeability coefficient, in centime ters per second (cm/sec), of the 4 drugs at 37° C were mea sured and are shown in Table 1. Table 1 PermeabiIity Molecular mass coefficient Drug (amu) (cm/sec) A 485 lO-5 B 500 10-6 C 515 10刁 D 530 10-8 \ ｀＼ Experiment 2 Equal numbers of cancer·c;ells were put into flasks containing 5.0 mL of nutrient medium. The cells were incubatedfor 1 hour at 37° C with 1 of the 4 drugs shown in 'fable 2. A control consisted of cells incubated in medium without any drugs. The cells were washed to remove residual drug traces and grown on nutrient plates for 7 days. During this time, the cells reproduced, forming colonies whicb were then counted. Plates with more colonieswere assumed to have morelivecells at the end of the 1-hour incubation. Table 2 shows the number of colonies counted. The drug-free control showed 30 colonies. Table 2 Drug concentration (µM)* Drug 1 5 10 25 A 22 11 4 。 B 26 21 10 1 C 28 23 11 2 D 30 25 12 3 *µM is micromolar Note: Numbers of colonies are averages for 3 replicates (identical samples). Experiment 3 Cells were handled as described in Experiment 2 with two exceptions: all drugs were tested at the same concen tration and incubation time was varied. Table 3 shows the number of colonies counted for Experiment 3. Table 3 Incubation time (hours) Drug 1 6 12 24 A 12 4 1 。 B 21 8 3 1 C 23 10 5 2 D 25 12 6 3 None 30 30 30 30 Note: Numbers of colonies are averages for 5 replicates.

AAdding 1g ofNaCl to the solutionBAdding 1g of CaC12 to the solutionCAdding 10mL of H20 to the solutionDAdding 1 g of NaCl and 1 mL of H20 to the

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Paper 86 · ACT January 2001 · Form 56B · Science Test

In Experiment 2, what was the relationship between drug concentration and the drug's effectiveness in killingcancer cells? _ re most effective at the highest con centration used. centration used. lowest concentration used while others were most effective at the highest concentration use�. between drug concentration and effectiveness. 6 12 24 incubation time(hours) 25 20 15 10 5 0 p a 1 u n o :, S :l ! U O ( O :l - 5 · 5 · - i } - } 4 心令、之令 } 、 g \ t . . 、、 . . 、入屯、＼飞鬼、 . . 、 \ ． t . 、、三yDrugA DrugB 二二".:....:B骂＄ -－－—None 6 12 24 incubationtime(hours) ACT-56B-SAMPLE 43 GO ON TO THE NEXT PAGE. 4 eoVIACT 泣惟学院微信号loviact 独角兽在这里 4 Passage V Heat flow is the escape of Earth's interiorheat through thelithosphere (crust and uppermantlecombined). Fora given thickness, high heat flow indicates a rapid tem perature increasewith depth. Figure 1 is a cross-sectional view of oceanic and continental lithospheres. Key continental lithosphere - - - - oceanic lithosphere 团 melting region with waterpresent 区 meltingregmn without waterpresent continental crust 0 50 100 ( 曰 ) 七 d ;:i p oceanic lithosphere (includes crust) Figure1 F_igure 2 shows heat flow, in watts per square meter (W/m2 ), for parts of the oceanic lith�sphe�e and the averageheat flows for both lithospheretypes. Figure3 shows the%'eragerelationship between tern peratureand depth for bo出lithospheretypes. Theshaded areas arewherelithosphere�aterial would melt with and without water. 00 90 80 70 60 50 40 30 20 10 ( 日 ) q � d g p 250 500 750 1,000 1,250 1,500 temperature(0 •\ Figure3 ` f averageheat flow oceanic litJ-iosph�re 62x 10-3WIm2 `！二三二三三 f i ° hot靡骂nal ；三g l hotn;nal con 飞；r 巳言ere Figure2 Figures adapted from Frank Press and Raymond Siever, Earth. ©1986 by W. H. Freeman and Co. ACT-566-SAMPLE 44 GO ON TO THE NEXT PAGE. 4 eov,ACT 拉馆字院微信号 loviact 独角兽在这里 4

Source page for act-january-2001-form-56b-science-025

AAll 4 d�ugs weBAll 4 drugs were most effective at the lowest conCSome of the drugs were most effective at theDBased on Experiment 2, there is no relationshipE30� —..—..—..一..一6Choice C — see source image

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Paper 86 · ACT January 2001 · Form 56B · Science Test

According to Figure 3, when comparing the properties of the continental lithosphere to those of the oceanic lithosphere, one would state that the continental litho sphere is: any depth. depth beneath 10 km. depth beneath 10 km. thinner than the oceanic lithosphere. J. ACT-568-SAMPLE 45 GO ON TO THE NEXT PAGE. 4 eOVIACT 拉馆学院微信号 loviact 独角兽在这里 4 Passage VI Scientists established 5 artificial marine ecosystems (A-E) to study the interactions of oil spills and organisms. Table 1 shows what was added to each ecosystem. Table 1 Ecosystem A B C D E Oil* ✓ ✓ ✓ ✓ Bacteria ✓ ✓ Phosphate fertilizer ✓ ✓ Lugworms ✓ ✓ ✓ ✓ ✓ Flounders (fish) ✓ ✓ ✓ ✓ ✓ *Oil was added at a concentration of 400 parts per million (ppm). ｀ The oil, bacteria, fert;ilizer, lugworms, and flounders were added in early Marcil.Figure 1 shows how the con centration of oil in Ecosystems B, C, D, and E, and the number of bacteria/mL in Ecosystems C and D changed over 16 months. Figure 2 shows how the number of lugworms/m2 changed over 16 months in each ecosystem. 125 100 75 E / S EJ O g m 。 J ;i q w n u z 50 25 Key Ecosystem: ..—..—A B .•••••••••• C ....…........…... D ----E ，／．：＼．．．．．． :·······、 ····· ............" ,•:- ; 、、．孕 ···· : 、心．．．．．．．．．．；·a．一` .........…············ :: 今： ,.I.,E·····…····· ．拿．．.. /_. 、、拿 \＿/交了。Mar. Jun. Sept. Figure 2 Dec. Mar. Jun. Figure 3 spows how the biomass of flounders in kilo- 3 grams/1,000 m'of water changed over 16 months in each ecosystem. Key Ecosystem: —..一A ••••••••• C .................. D 一一一 E Key oilconcentrationinEcosystem: ------c ························ D —-－－- - E bacteria concentrationinEcosystem: －－一一..—c 一·一·—I) 30 0 0 2 1 ( J ;J j U M J O , W 0 g . I 泌 1 ) SJ ;i p a n o u J O S S U W O ! q ·····································飞．一；；；；；；；；；；”“”“;“r;;；r:.?．飞．．；二．一：；r：：沪千俨．． ..• ＿一一＿一一一．一：··,-－·一·一�--:-:-:.�-..立一＿一＿ ` _- ．．．一一 .. ＿－ .•--－－－－．一．-• ··········•·•·•····························································· , .. ,_.. 一－－－＿一一 400 350 300 250 200 150 100 ( e d d ) u o n e n u 8 u 8 I - o 50 。Mar. `\＼＼ \： '<.. ，六、 //＼ ar T E P 亡 ;i p u q .J O 1 ;i q w n u 000 000 000 000 邸 000 000 000 000 000 0 g 叽 g 陨 60 玑矶玑泣凡。Mar. Jun. Sept. Figure 3 Dec. Mar. Jun. ACT-56B-SAMPLE Jun. Jun. Figure 1

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Athe same temperature as the oceanic lithosphere atBhotter than the oceanic lithosphere at any givenCcooler than the oceanic lithosphere at any givenDChoice J — see source image

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Paper 86 · ACT January 2001 · Form 56B · Science Test

Based·on the information presented, which of the fol lowing statements about the relationship between the electron's orbit numberand the energy of the hydrogen atom is most likely true? energy of the hydrogen atom increases. _ energy·of the hydrngen atom decreases, energy of the hydrogen atorh increases and then decreases. _ J. As the electron's orbit number inc.i-eases, the energy of the hydrogen atom remains the same. END OF TEST 4 STOP! DO NOT RETURN TO ANY OTHER TEST. 、 , I ACF56B·SAMPLE 49 2001 ACT 56B English Mathematics Readling Science 1 B L 1 E 31 B 1 C 1 B 2 G O 2 H 32 J 2 G 2 J 3 D V 3 C 33 B 3 A 3 A 4 J I 4 J 34 F 4 J 4 F 5 C 5 A 35 B 5 C 5 A 6 H 41 C 6 J 36 K 6 H 6 J 7 A 42 H 7 A 37 D 7 D 7 B 8 J 43 A 8 K 38 F 8 G 8 H 9 C 44 G 9 C 39 B 9 B 9 B 10 J 45 A 10 H 40 G 10 H 10 H 11 A 46 G 11 A 41 D 11 D 11 A 12 H 47 B 12 F 42 F 12 H 12 G 13 D 48 H 13 C 43 D 13 B 13 D 14 G 49 D 14 K 44 F 14 J 14 F 15 D 50 F 15 B 45 C 15 D 15 B 16 F 51 A 16 K 46 K 16 F 16 H 17 B 52 G 17 C 47 E 17 B 17 B 18 G 53 D 18 J 48 K 18 H 18 H 19 A 54 F 19 E 49 D 19 D 19 C 20 J 55 C 20 K 50 J 20 F 20 G 21 B 56 G 21 C 51 B 21 C 21 A 22 J 57 A 22 F 52 F 22 J 22 J 23 C 58 H 23 C 53 C 23 C 23 B 24 H 59 C 24 F 54 F 24 F 24 F 25 D 60 F 25 B 55 E 25 D 25 A 26 F 61 B 26 G 56 G 26 F 26 J 27 C 62 F 27 D 57 A 27 A 27 D 28 F 63 D 28 K 58 G 28 H 28 F 29 B 64 G 29 C 59 D 29 D 29 B 30 F 65 C 30 J 60 J 30 G 30 H 31 D 66 H 31 A 31 C 32 J 67 B 32 H 32 H 33 C 68 J 33 A 33 C 34 H 69 A 34 J 34 J 35 B 70 H 35 B 35 B 36 G 71 C 36 H 36 F 37 C 72 J 37 C 37 A 38 J 73 B 38 G 38 J 39 A 74 J 39 B 39 C 40 J 75 A 40 G 40 F : loviact QQ 411-279-476 loviact.com 2016 Lovi TABLE 1 Procedures Used to Obtain Scale Scores from Raw Scores On each of the four tests on which you marked any responses, the total number of correct responses yields a raw score. Use the table below to convert your raw scores to scale scores. For each lest, locate and circle your raw score or the range of raw scores that includes it in the table below. Then, read across to either outside column of Ihe table and circle the scale score that oorresponds to that raw score. As you determine your scale scores, enter them in the blanks providad on the right. The highest possible scale score for each test is 36. The lowest possible scale score for any test on which you marked any responses is 1. Next, compute the Composit8 score by averaging the four scale scores. To do this, add your four scale scores and divide the sum by 4. If the resulting num- ber ends in a fraction, round it off to the nearest whole number. (Flound down any fraction less than one-half., round up any fraction that is one-half or more.) Enter this number in the blank. This is your Composite score. The highest possible Composite score is 36. Thé lowest possible Composite score is 1 . ACT Test 0556B Your Scale Score English Mathematics Reading Science Sum of scores Composite score (sum - 4) NOTE: 11 you left a test completely blank and marked no items, do not lisl a scale score for that lest. If any tesl was completely blank, do not calculate a Composite score. Now go to page 55 and use the table to convert raw scores on the subscor8 araas to scale subscores. y.. loviact Raw Scores Scale Score Test 1 English Test 2 Mathematics Test 3 Reading Test 4 Science Scale Score 36 35 34 33 32 31 30 29 28 27 26 25 24 28 22 21 20 19 18 17 16 15 14 13 12 11 10 75 74 ',72-73 71 60 59 40 39 38 37 36 35 40 39 38 58 56-57 54-55 52-53 50-51 48-49 46-47 44-45 42-43 40-41 38-39 36-37 34-35 31-33 28-30 25-27 22-24 18-21 16-17 13-15 11-12 08-10 07 05-06 33 32 31 30 29 37 36 35 34 33 32 31 29-30 28 27 25-26 23-24 22 20-21 18-19 16-17 15 13-14 12 67-68 65-66 63-64 60-62 58-59 56-57 53-55 51-52 49-50 46-48 43-45 40-42 37-39 31-33 27-28 25-26 23-24 21-22 19-20 17-18 14-16 11-13 09-10 05-06 04 02-03 00-01 34 32-33 31 30 29 27-28 26 24-25 23 22 20-21 19 27 26 25 24 23 22 21 20 19 18 17 16 15 14 13 12 11 10 17 16 14-15 13 11-12 09-10 08 07 06 05 04 10 08-09 07 06 05 04 03 02 04 03 02 03 02 01 00 01 01 00 00

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AAs the electron's orbit number increases, theBAs ttie electron's -orbit number increases, theCAs the electron's orbit number increases, the 34.36 29.30 07.08DChoice J — see source image

Form 56B · Science Test · 40 questions

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